OPERATING PRINCIPLE

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Explanations on the level of the school physics course

     Everyone knows that an electron has a negative charge in an atom, and the nucleus of an atom has a positive charge. Getting in the magnetic field, an electron is attracted to the South Pole (S), and the core — to the North Pole (N).

     Liquid fuels (gasoline, diesel, condensed gas) are a mixture of different products (hydrocarbons). Each of the components of the fuel has its own chemical composition, its own physical and chemical properties, its structure and size of the molecules.
     The Lorentz forces (do you remember from school the «rule of the left hand» or the “right-hand thumb rule”) impact the charged particles in a magnetic field.
     In the Activator, the magnetic fields change their directions by 180 degrees (Fig. on the left).

     The nucleus (a positive particle) is attracted to the N, and the electrons (negative particles) tend to the S. While going through the changing magnetic fields of the Activator, electrons begin to cluster at the S, and the nucleus — at the N (Fig. on the right).

     The atoms in molecules and the molecules themselves start already to fluctuate at 180 degrees. That is, a polarization of the molecules themselves already occurs.

These fluctuations can momentarily disrupt or change the nature of the connections between atoms in molecules and between molecules themselves.

     Getting in the magnetic field, both the electron and the nucleus change their motion according to the direction of the force lines of the magnetic field. Is it so?

And the direction of the magnetic field lines in the Activator is changed to 180 degrees.

     It means, that the electrons and the nucleus also change their direction of motion of 180 degrees. And so, 10 times (in the set of the Activators, there are 10 magnetic fields).

Well, what do you think will happen with the structure of the fuel molecules after such “turbulence”?

     When destroyed or disrupted, the connections of fuel molecules start faster and easier to react with oxygen (they oxidize, burn). This state of the molecules does not last long (20 – 30 minutes). Then all the molecular connections are restored, and everything acquires its original state.

 

    You agree that the split log BURNS much BETTER than the whole piece of wood … THE SAME HAPPENS WITH THE FUEL!
     As a result of this, the fragile bonds between molecules are disconnected (intermolecular bonds). But it already leads to a DECREASE IN VISCOSITY AND DENSITY OF THE FUEL.

The comparative characteristics of diesel fuel, treated by the fuel combustion Promoter

Fuel characteristics

Unit of measurement

Standard fuel

 Fuel after the Activator

Kinematic viscosity

   mm 2/s

       5

       3,11

Density

   g/cm3

     0,93

       0,81

Flash-point

    °С

       88

       70,2

The net calorific value

   kJ/kg

    42633

      44520

     The table above shows that the fuel which has passed through the Fuel combustion Activator has significantly lower density and viscosity.

      And this already means that:

1. The angle of fuel spray by the diesel nozzles is increased.
2. The particles of fuel in the fuel-air mixtures have much smaller size.

These factors greatly affect the fuel combustion improvement and increase of the engine power.

     The fuel flash point reduction improves the engine starting in the cold weather.
     Increasing of the heat combustion leads to the fuel savings. That is, LESS fuel is needed to perform the same work of the engine.

Destruction of gasoline hydrocarbons

Directions of the gasoline hydrocarbon destruction after treatment with the magnetic fields.

The original molecule and its combustion heat (Q, MJ/kg)

Destruction products

Heat of combustion

(Q, MJ/kg)

С10Н22   Q = 44,602

2C5Н10  + 2H

46,722;4,75%

5Н10   Q = 45,008

3Н6 + 2С2Н4

= 46,35;+3%

С6Н14   Q = 44,769

2C3Н6 + 2Н

3C2Н4  + 

=48,654;+ 8,68%

= 48,873;+ 9,17%

С4Н8   Q = 45,322

2Н4

=47,180;4,1%

C8H16   Q = 43,775

2C4Н8

2Н4

=45,322;+ 3,5%

= 47,180;+ 7,8%

С9Н12   Q = 41,6

3Н4

= 46,164;+ 11%

С10Н14 Q = 41,76

3Н4 + 2С2Н2 +2Н

= 46,701;+ 11,8%

С11Н16  Q = 42,023

3Н+ С2Н4

= 46,674;+ 11%